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8x^2-27x+2=0
a = 8; b = -27; c = +2;
Δ = b2-4ac
Δ = -272-4·8·2
Δ = 665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{665}}{2*8}=\frac{27-\sqrt{665}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{665}}{2*8}=\frac{27+\sqrt{665}}{16} $
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